267 Miles - 429 Km
4 hours 58 mins

Distance From Osage Beach, MO to Searcy, AR

Driving Distance

267 Miles

429 Km

4 hours 58 mins

Flight Distance

207 Miles

333 Km

56 mins

Gas and Emissions

12.36 Gallons

Fuel Needs

0.91 Pounds CO2 fp per miles

Distance, Gas Consumption and Emission Notes

Distance from Osage Beach, MO to Searcy, AR is 267Miles or 429 Km. You can get this distance about 4 hours 58 mins. If you want to planning travel with plane, you can get this distance about 56 mins .

A car with an average MPG will needs 12.36 gallons of gas to get the route between these points.

The estimated cost of gas to get between Osage Beach, MO and Searcy, AR is $28.06.

During the route, an average car will release 242.16 pounds of CO2 to the atmosphere. Your carbon footprint is 0.91 pounds of CO2 per mile.

* Average US MPG used for calculations is 21.6 MPG.
* Average US gas price used for calculation is 2.27 per gallon.
* Coordinates of Osage Beach, MO is 38.1502735, -92.6179101 and coordinates of Searcy, AR is 35.2467436, -91.7336848